22. In the adjoining figure AO =BO, and ∠=∠b,
a. Is ∠=∠?(ℎ)
b. Is ∆ ≅∆(ℎ).
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1
Answer:
In ∆AOB and ∆COD,
∠AOB=∠COD (Vertlcally opposite angles)
OC
AO
=
OD
BO
(given)
Therefore according to SAS similarity criterion, ΔAOB∼ΔCOD
∴
OC
AO
=
OD
BO
=
DC
AB
⟹
2
1
=
2
1
=
DC
5
⟹
2
1
=
DC
5
⟹DC=10cm
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