Question

ОХ
22. In the adjoining figure, OPQR is a square. A circle
drawn with centre O cuts the square in X and Y.
Prove that QX - QY
​

Answer 1

Join OX and OY

In ΔORX & ΔDPY

∠ORX=∠OPY=90

OX=OY (radii)

OR=OP (side of square)

∴ΔORX≅ΔOPY by RHS

Hence, RX=PY (side of square)

Now QR=QP

QX+RX=QY+PY

⇒QX=QY

I hope this helps you

Please mark me the brainliest

Answer 2

Answer:

ОХ

22. In the adjoining figure, OPQR is a square. A circle

drawn with centre O cuts the square in X and Y.

Prove that QX - QY