Question

22. In the given figure, AB || CD. If AOC = 30°
and OAB = 100° then OCD = ?
- (a) 130°
(b) 150°
(c) 80°
(d) 100°​

Answer 1

From O, draw E such that OE || CD || AB.

OE || CD and OC is traversal.

So,

DCO + COE = 180 (co –interior angles)

x + COE = 180

COE = (180 – x)

Now, OE || AB and AO is the traversal.

BAO + AOE = 180 (co –interior angles)

BAO + AOC + COE = 180

100 + 30 + (180 – x) = 180

180 – x = 50

X = 180 – 50 = 130O

Answer 2

This is your ANSWER

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