22. In vector diagram shown in figure where (R) is the
resultant of vectors (A) and (B).
If R = To, then value of angle o is :
(1) 30°
(2) 45°
(3) 60°
(4) 750
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Given that,
R = \dfrac{B}{\sqrt{2}}R=
2
B
The resultant vector is
R = \dfrac{B}{\sqrt{2}}R=
2
B
\dfrac{R}{B}=\dfrac{1}{\sqrt{2}}
B
R
=
2
1
According to figure,
Base = A
Perpendicular = R
Hypotenuses = B
Sin\theta = \dfrac{perpendicular}{Hypotenuses}Sinθ=
Hypotenuses
perpendicular
sin\theta=\dfrac{R}{B}sinθ=
B
R
sin\theta=\dfrac{1}{\sqrt{2}}sinθ=
2
1
\theta=sin^{-1}\dfrac{1}{\sqrt{2}}θ=sin
−1
2
1
\theta= 45^{\circ}θ=45
∘
Hence, The value of the angle is 45°.
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