22 is the smallest no. then find other no. of phythagorean triplet
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In Pythagorean triplet
there are three numbers
2m
m^2+1
m^2-1
so put 22 as any of them
take 2m=22
so m=11
.
then m^2+1= 11^2+1 = 121+1 =122
and
m^2-1 = 11^2-1 =121-1 = 120
then the three no.s are
22 , 120 , 122
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there are three numbers
2m
m^2+1
m^2-1
so put 22 as any of them
take 2m=22
so m=11
.
then m^2+1= 11^2+1 = 121+1 =122
and
m^2-1 = 11^2-1 =121-1 = 120
then the three no.s are
22 , 120 , 122
THANK U
●●●●●●●●●●●●
HOPE HELPS
PLEASE MARK IT AS BRAINLIEST
☆☆☆☆☆☆☆☆
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