Question

22 IU + 9
23 Use (a + b)2 = a2 + 2ab + b2 to evaluate the following:
(i) (101)
(ii) (1003)2
(iii) (10-2)​

Answer 1

Answer:

Step-by-step explanation:

using (a+b)2=a2+b2+2ab

i) (100+1)2 = (100)2+(1)2+ 2X100X1 = 10000+1+200 =10201

ii) (1000+3)2= (1000)2+(3)2+2X1000X3 = 1000000+9+6000 =1006009

iii) (10-2)2= (10)2 + (2)2 - 2X10X2=100+4-40= 104-40 =64

in iii i used (a-b)2 = a2+b2-2ab