Question

22
Length, breadth, height of cuboidal
shape box is 7 cm, 6 cm, 4 cm.find
surface area of the vertical faces of
box *
(2 Points)
104
38​

Answer 1

Answer:

• Surface area of the vertical faces of the box is 104 cm².

Step-by-step explanation:

Given that:

• Length of the cuboidal shape box = 7 cm

• Breadth of the cuboidal shape box = 6 cm

• Height of the cuboidal shape box = 4 cm

To Find:

• Surface area of the vertical faces (VSA) of the box.

Formula Used:

• Vertical surface area of cuboid = 2(L + B) × H

Where,

• L = Length of the cuboid
• B = Breadth of the cuboid
• H = Height of the cuboid

Substituting the values,

$\sf{VSA \;of \;the\; cuboid\; box = 2(7 + 6) \times 4}$

Opening the bracket,

$\sf{\hookrightarrow2\times13 \times 4}$

Multiplying the numbers,

$\sf{\hookrightarrow 104}$

Hence, vertical surface area (VSA) of the cuboid is 104 cm².

More Formulas:

• Volume of a cuboid = (L × B × H)
• Diagonal of a cuboid = $\sf\sqrt{L^2+B^2+H^2}$
• Total surface area of a cuboid = 2(LB + BH + LH)

Answer 2

Answer:

104 cm²

Step-by-step explanation:

Given -

Dimensions of cuboidal shape box =

Length (l) = 7 cm

Breadth (b) = 6 cm

height (h) = 4 cm

To find -

Surface area of the vertical faces of box

Solution -

surface area of vertical faces of box = lateral surface area of cuboid (L.S.A.)

= 2(lh+bh) = 2(l+b)h

= 2×(7 cm + 6 cm) × 4 cm

= 2×4 cm × (7 cm + 6 cm)

= 8 cm × 13 cm

= 104 cm²

Hence the surface area of vertical faces of box = 104 cm²

hope it helps.