22
Mathematics for Class
3
4. On one day a rickshaw puller earned 160. Out of his earnings he spent 26
on tea and
5
1
2
snacks, 50 on food and 16 on repairs of the rickshaw. How much did he save on that
2
5
day?
3
Answers
Answer:
66.5 Rs
Step-by-step explanation:
Hi there !!!
Total earnings = 160Rs
Total expenses = 26 3/5 + 50 1/2 + 16 2/5
= 133/5 + 101/2 + 82/5
= 266/10 + 505/10 + 164/10
= 935/10
= 187/2 Rs
So total savings = Total earnings - Total expenses
= 160 - 187/2
= 320/2 - 187/2
= 133/2 or 66.5 Rs
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Answer:
Step-by-step explanation:
We know that the given details are
Total earnings =Rs.160
Earnings spent on tea and snacks =Rs.26
5
3
Earning spent on food =Rs.50
2
1
Earnings sped on repairs =Rs.16
5
2
∴ Total expenditure = Earnings spent on tea and snacks + Earnings spent on food + Earnings spent on repairs
=Rs.26
5
3
+Rs.50
2
1
+Rs.16
5
2
=
5
133
+
2
101
+
5
82
By taking LCM for 5 and 2 is 10
=
10
(133×2+101×5+82×2)
=
10
(266+505+164)
=
10
935
Total Savings = Total Earnings − Total Expenditure
=Rs.160−Rs.
10
935
By taking 10 as the LCM
=
10
(160×10−935×1)
=
10
(1600−935)
= Rs.66 2\1
∴ Total Savings on that day is Rs.66 2\1