Question

22. px + p²x + pqy + qy - (px + qy)2 +​

Answer 1

Step-by-step explanation:

Px+qy=p-q ---------(1)

qx-py=p+q ---------(2)

Multiplying (1) with p and (2) with q we get,

p²x+pqy=p²-pq -----------(3)

q²x-pqy=pq+q² -----------(4)

Adding (3) with (4) we get,

p²x+q²x=p²+q²

or, x(p²+q²)=p²+q²

or, x=1

Putting in (1) we get,

p.1+qy=p-q

or, qy=p-q-p

or, qy=-q

or, y=-1

∴, x=1 and y=-1