Question

22. sinA .cot A + cos A .tanA=1​

Answer 1

Step-by-step explanation:

sinA*cosA\sinA plus cosA*sinA\cosA

here sinA and sinA get cancel remain cosA

and cosA and CosA get cancel remain sinA

so now cosA plus sinA remains

as per identity sinA plus cos A = 1

hence proved

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