Question

22. Solve for x: 3(x+2)+3*=10​

Answer 1

Just like this

1. Solve: x^2 = 36

x^2 = 36

or, x^2 - 36=0

or, (x + 6)(x - 6) = 0

So, one of x + 6 and x - 6 must be zero

From x + 6 = 0, we get x = -6

From x - 6 = 0, we get x = 6

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Thus, the required solutions are x = ± 6