Question

22. Solve: ix2 + 4x - Si = 0.​

Answer 1

Step-by-step explanation:

Given as ix2 – 4x – 4i = 0 ix2 + 4x(–1) – 4i = 0 [as we know, i2 = –1] Therefore by substituting –1 = i2 in the above equation, we get ix2 + 4xi2 – 4i = 0 i(x2 + 4ix – 4) = 0 x2 + 4ix – 4 = 0 x2 + 4ix + 4(–1) = 0 x2 + 4ix + 4i2 = 0 [Since, i2 = –1] x2 + 2ix + 2ix + 4i2 = 0 x(x + 2i) + 2i(x + 2i) = 0 (x + 2i) (x + 2i) = 0 (x + 2i)2 = 0 x + 2i = 0