Question

22 t
avax - 6
$find \: zeros \: of \: polynomial \: {x }^{2} + 2 \sqrt{2x} - 6$
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Answer 1

Step-by-step explanation:

• ${x}^{2} + 2 \sqrt{2}x - 6$
• $= > {x}^{2} + 3\sqrt{2} x - \sqrt{2} x - 6$
• $= > x(x + 3 \sqrt{2} ) - \sqrt{2}(x + 3 \sqrt{2} )$
• $= > (x + 3 \sqrt{2} )(x - \sqrt{2} )$
• Now for the zeros :-
• $x + 3 \sqrt{2} = 0 \: \: \: and \: \: x - \sqrt{2} = 0$
• $= > x = - 3 \sqrt{2} \: \: \: \: and \: \: x = \sqrt{2}$
• These are required zeros. I hope it will help you. Thank you