Question

22. The angle of elevation of the top of a vertical tower on a level ground from point at a distance of
93 m from its foot on the same ground is 60". Find the height of the tower. need a brief answer​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

The height of the tower is approximately 160.89 m.

Explanation:

Let the point be A.

Given : The angle of elevation of the top of a vertical tower on a level ground from A = 60°

The distance of  from its foot on the same ground and A = 93 m

let h be the height of the tower.

According to the trigonometry ,

$\tan60^{\circ}=\dfrac{h}{93}$

Put $\tan60^{\circ}=\sqrt{3}$ , we get

$\sqrt{3}=\dfrac{h}{93}$

$h=93\sqrt{3}$

$h=93(1.73)=160.89$

Hence, the height of the tower is 160.89 m.

# Learn more :

The angle of elevation of the top of a vertical tower on a level ground from point, at a distance of 9 root 3 m from its foot on the same ground is 60 degree . Find the height of the tower.

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