Question

22. The base of a right triangle 3 points
is 48cm and it's hypotenuse is
50cm long. The area of the
triangle is *
O 168 sq cm
O 252 sq cm
O 336 sq cm
504 sq cm​

Answer 1

Case of right angled triangle :-

base = 48cm

hypotenuse= 50cm .

By Pythagoras theorem , we get

{h}^{2} = {b}^{2} + {p}^{2}h2=b2+p2

So ,

{p}^{2} = {h}^{2} - {b}^{2}p2=h2−b2

= > {p}^{2} = {50}^{2} - {48}^{2}=>p2=502−482

= > {p}^{2} = 2500 - 2304=>p2=2500−2304

= > {p}^{2} = 196=>p2=196

= > p = \sqrt{196}=>p=196

= > p = 14=>p=14

So ,

Perpendicular = 14 cm .

Now area of triangle = 1 / 2 * b * p

= 1 / 2 * 48 * 14

= 48 * 7

= 336 cm²

HOPE IT HELPS YOU

Answer 2

Answer:

336

Step-by-step explanation:

Pythagoras theorem:- h² = p² + b²

p² = h² - b²

p² = 50² - 48²

p² = 196

p = 14

Area = ½ × b × h

Area = ½ × 14 × 48 = 48 × 7 = 336