Question

22) The following numbers 3,7,9,13,15,17,20,32,45,76,83,99,100 are written on different tokens and put in a box. A token is selected at random from the box. Find a) the probability of getting an odd number. b) the probability of getting a multiple of 5. c) the probability of getting a two-digit number

Answer 1

Answer:

3 , 7 , 9 , 13 , 15 , 17 , 20 , 32 , 45 , 76 ,83 , 99 , 100

total number is = 13

a) the total number of odd number in the data is = 9

    probability is = 9/13

b) total number of multiple of 5 = 4

   probability is = 4/13

c) total number of two - digit number is = 9

   probability is = 9/13

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Answer 2

Answer:

Total number of possible outcomes = 13

1. 3
2. 7
3. 9
4. 13
5. 15
6. 17
7. 20
8. 32
9. 45
10. 76
11. 83
12. 99
13. 100

(a) Total number of possible outcomes = 13

    Number of favourable outcomes = 9

1. 3
2. 7
3. 9
4. 13
5. 15
6. 17
7. 45
8. 83
9. 99

   Therefore,

   P(getting an odd number) =

   $\frac{No. of favourable outcomes}{Total number of possible outcomes }$

   = 9/13

(b) Total number of possible outcomes = 13

    Number of favourable outcomes = 4

1. 15
2. 20
3. 45
4. 100                          

    Therefore,

     P ( getting a multiple of 5) = $\frac{No. of favourable outcomes}{Total number of possible outcomes }$

     = 4/13

 (c)  Total number of possible outcomes= 13

      Number of favourable outcomes = 9

1. 13
2. 15
3. 17
4. 20
5. 32
6. 45
7. 76
8. 83
9. 99

    Therefore,

     P ( getting a two-digit number) = $\frac{No. of favourable outcomes}{Total number of possible outcomes }$

     =9/13