Physics, asked by Anonymous, 15 days ago

22) The intensity of earth's magnetic field at the surface of earth is of the order of
(1) 11
(2) 10-31
(3) 10-1 G
(4) 10-5 T

23) At a certain place, the horizontal component of earth's magnetic field is v3
times the vertical component. The angle of dip at that place is
(1) 30°
(2) 609
(3) 90°
(4) 45°​

Answers

Answered by Parthkr
2

The intensity of earth's magnetic field at the surface of earth is of the order of

Answer- 10^-5T

At a certain place, the horizontal component of earth's magnetic field is v3

times the vertical component. The angle of dip at that place is

Answer - 60°

Answered by luciacanns
1

Answer:

22) Earth's magnetic field is of the order 10*-5 T (4).

23) Let us consider the earth's magnetic field (B) divided into a horizontal (Bh) and vertical component (Bv) with an angle of 90 degrees in the middle( visualise a right angled triangle).

Angle of dip= tan delta= Bv/Bh

Now Bh= root 3( Bv), therefore substituting in the above formula-

Angle of dip= tan delta= 1/ root 3

Angle of dip= 30 degrees (1)

Explanation:

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