Chemistry, asked by maitreyeeghanote84, 10 months ago

22.) The ionization enthalpy of He- iron is 19.60 x 10-** J atom-t. The ionization en
at 84.23 10- atom-1
b) 44.10 x 10-3 Jatom.
63.20 x 104 atom-1
d.) 21.20 x 10-15 atom-1
e.) 2.17 x 10.1 atom-1​

Answers

Answered by 5003427purvithaj2
0

Explanation:

Since IE Li 2+/IE He + =( Z Li 2+/Z H+) 2 = 9/4

Since IE Li 2+/IE He + =( Z Li 2+/Z H+) 2 = 9/4∴IELi2+= 9/4×IE He+=9/4×19.6×10 −18

Since IE Li 2+/IE He + =( Z Li 2+/Z H+) 2 = 9/4∴IELi2+= 9/4×IE He+=9/4×19.6×10 −18 =4.41×10−17J/atom

Since IE Li 2+/IE He + =( Z Li 2+/Z H+) 2 = 9/4∴IELi2+= 9/4×IE He+=9/4×19.6×10 −18 =4.41×10−17J/atomEnergy in stationary state =−IE=−4.41×10 −17J/atom

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