Math, asked by gourav71666, 11 months ago

22. The population of a village was 4000 in January 2014
Since then if the population increased by 10% every
year, what would be the population of the village in
January 2017?​

Answers

Answered by NachiketaG
4

Answer:

Population in Jan 14 = 4000

rate of increase per annum = 10%

time =3 years

Applying Compound Intrest formula

1st year = 4000 [ 1+ 10/100]^1

= 4000* 11/10 =4400

2nd year = 4400 * 11/10 = 4840

3rd year = 4840 *11/10 = 5324

Therefore, in 2017 the population will be 5324

Answered by abusaquib017
12

Answer:

5324

Step-by-step explanation:

4000×10/100=400 people increased till Jan 2015

total population=4000+400

4400.

population increase in period jan2015 to jan2016

4400×10/100

=440 people

then total population till Jan 2016.

4400+440=4840.

and lastly in period Jan 2016 to Jan 2017

4840×10/100=484 people increased

so total population till Jan 2017..

4840+484=5324 population..

I Thik it's enough explanation...

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