Question

22. The present population of a town is 2,00,000. Its population increases by 10% in the first year
and 15% in the second year. Find the population of the town at the end of two years.
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Answer 1

Answer:

Step-by-step explanation:

Given,

Present population of a town is 2,00,000.

Its population increases by 10% in the first year.

Its Population increases by 15% in second year.

To Find :-

Population of the town at the end of two years.

Solution :-

1)  population increases by 10% in the first year.

$\implies 10\%\times Present\:population$

$=\dfrac{10}{100}\times 2,00,000$

$=\dfrac{2,00,000}{10}$

= 20,000

Population in the first year = 20,000 + 2,00,000

= 2,20,000

2) Population increases by 15% in second year.

$\implies 15\%\times Population\:in\:first\:year$

$=\dfrac{15}{100}\times2,20,000$

$=15\times 2,200$

= 33,000

Population in the second year = 33,000 + 2,20,000

= 2,53,000

Since the population at the end of two years = 2,53,000

Answer 2

Given:

• Present population of town is 200000
• Population increased in first year = 10%
• Population increased in 2nd year = 15%

To find:

• Population of town after 2 years.

Solution:

As given that present population of town is 200000 and 10% population increased is 1st year.

Therefore,

Population of city after 1 year = $\large{\sf{\dfrac{110×200000}{100}}}$

→ Population of town after 1 year = $\dfrac{22000000}{100}$

→ Population of town after 1 year = 220000

Now,

Present population (after 1 years) of town is 220000 and again population increased 15%.

Therefore,

Population of town after 2 years = $\large{\sf{\dfrac{115×220000}{100}}}$

→ Population of town after 2 years = $\dfrac{25300000}{100}$

→ Population of town after 2 years = 253000

Hence,

• $\small{\boxed{\sf{Population\:of\:town\: after\:two\:years\:will\:be\:253000}}}$