Question

22.
The taxy fare in a city is a
followes : tool the first kilomete
the fare is Rs 12 and for the subs
distance it is Rs 8 per km. Taking t.
distance covered as x km and to
fare as Rs y, write a linea
equation for this information
and draw it graph.​

Answer 1

Explanation:

I was not having scale bcz of lockdown:(((

Answer 2

Answer:

(0,4) and (1,12)

Explanation:

Total distance covered = x km

Fare for 1st km = Rs 12

Fare for rest of the distance = Rs 8 * Remaining distance

= Rs. 8 (x-1)

Total fare = Fare for 1st km + fare for the rest (x-1)km

y = 12 + (x-1)8

y = 12 + 8x - 8

y = 8x+4

To draw graph, we need at leasty two solutions of equations.

Putting x = 0, we get,

y = 8(0) + 4

y = 0 + 4  

y =  4

So (0,4) is a solution of the equation.

Putting x = 1,

y = 8(1)+4

y = 8 + 4

y = 12

So (1,12) is a solution of the equation.

Plot the mentioned points to draw a graph.

(0,4) and (1,12)

Mark me brainliest :))))