22. The value of k so that the point (7,3), (-1,0) & (k,-2) are vertices of a right
angled triangle at (-1,0) will be:
A)-3
B)-2
C)-1 D)0
Give me solution.
Answers
Answered by
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Step-by-step explanation:
AC^2=AB^2+BC^2
AC^2=K^2+49-14K+25
AB^2=73
BC^2=K^2+1+2K+4
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