22. There is a path of width 5 m. around a square shaped park of length
100 m. Find the area of the park.
23. There is a path of width 6 m, along the outer houndoru
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Answered by
1
Given inner side of square park, s=100 cm
Area of inner square =100²
=10000 cm²
width of path,w=5 cm
Outer side of square =100+5+5=110 cm
Area of outer square =110²
=12100 cm²
Area of path =12100−10000=2100 cm²
Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500
∴ Cost of cementing a 2100 cm²
path =Rs. 52500
Hope it helps.........
Answered by
1
Step-by-step explanation:
without path the length of the square shaped park is (100-5×2)m=90m
so the area of the park is 90×90 sqm=8100sq m
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