Question

22. Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once. Find the probabilitythat the sum of the two numbers occurring on their top faces is more than 7.​

Answer 1

Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once. The probabilitythat the sum of the two numbers occurring on their top faces is more than 7 is 5/12

Step-by-step explanation:

When two dices are rolled simultaneously

The total number of outcomes $=6\times 6=36$

The sum of the two numbers on the top of the faces will be more than 7 when the outcome is

$(2,6),(3,6),(3,5),(4,6)(4,5),(4,4),(5,6),(5,5),(5,4),(5,3),(6,6),(6,5),(6,4),(6,3),(6,2)$

Therefore, total number of favourable outcomes = 15

Therefore, the probability that the sum of the numbers if more than 7

= Number of favourable outcomes / Total number of outcomes

$=\frac{15}{36}$

$=\frac{5}{12}$

Hope this helps.

Know More:

Q: Two dice (each bearing number 1 to 6)are rolled together. Find the probability that the sum of the numbers on the upper most faces of two dice is (i) 4 or 5 . (ii) 7 , 8 or 9 . (iii) between 5 and 8. (iv) more than 10.

Click Here: https://brainly.in/question/2384312

Q: Similar question

Click Here: https://brainly.in/question/14249473

Answer 2

Answer:

5/12 is the answer.....