Question

22. Two point charges q1 = 400 *10^-6 C and q2 = 100 *10^-6C are
kept fixed, 60 cm apart in vacuum. Find intensity
of the electric field at mid-point of the line joining
q1 and q2.
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Answer 1

E=kq1/r^2 where r is 30 cm Becaz mid point par find karna hai 60cm ke and dirn away from charge and for 2nd charge E=kq2/r^2 where r is 30 cm and dirn away from this charge means at mid point two electric field but opposite in dirn then jiska charge jada hai vo dominant hoga aur ussi ki dirn bhi hogi and dono field ko minus karne se ans net E aa jayega