22.
Two vector Ā = 3i+8j-2k and B = 6i+16j+ xk are such that the component of B perpendicular to
A is zero. Then the value of x will be:
[ ]
1) 8
2-4
3) +4
4 - 8
Answers
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2
Answer:
The value of x= - 4
Explanation:
Given,
A = 3i + 8j - 2k
B = 6i + 16j + xk
The component of B is perpendicular to A is zero. Then, #A×B =0
So, by determinant method, we get,
(8x + 32)i - (3x+12)j + (48 - 48)k = 0 = 0i + 0j + 0k
==> So, (8x+32) = 0 (OR) (3x+12) = 0
==>8x = -32 3x = -12
x = -4.
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