Question

22. Write the Nernst equation and compute
the emf of the following cell at 298 K.
Sn(s) Sn2+ |H JH,, 1 atm | Pt
(0.05 M) (0.02 M)
[ES2+1sn =-0.144 V All India 20110​

Answer 1

Answer:

rxn Is Sn(s) +2H+(aq)↔ Sn2+(aq) + H2(g)

Nernst equation

Ecell =E°cell - 0.059 /n logkc.

n=2

Ecell =0.14- 0.059 /2 log(0.05)/(0.02)²

Ecell =0.14-0.059/2 log(125)

Ecell =0.14-0.059/2 (2.0969)

Ecell =0.14-0.062 V

Ecell =0.078 V ( Ans.)