Math, asked by surabhiashutosh, 1 year ago

22\x+y + 15/x-y = 15
55/x+y +45/x-y = 14

Answers

Answered by ankalaanu
3

Answer:

Let 1/x+y=a and 1/x−y = b

Hence

22/x+y +15/x-y =5 → 22a+15b=5 ...........(i)

and and 55/x+y + 45/x-y = 14 → 55a+45b=14.......(ii)

Multiply (i) by 3 and subtract from (ii) and get

−11a=−1 i.e a= 1/11

From (i) b=(5−22a)/11 ={5−22×(1/11)}/15= 1/5

Since 1/x+y=a → 1/x+y=1/11 i.e x+y =11 .(ii)

and and 1/x−y = b → 1/x−y = 1/5 i.e x−y = 5 (iv)

Solving (iii) and (iv) gives x= 8 and y= 3

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