Question

220 J of heat is produced each second in a 8 ohm resistor. Find the potential difference across the resistor.​

Answer 1

HEAT = I²RT

I×IRT

SINCE, V = IR

HEAT = IVT

220 = V/R × VT

220 = V²T/R

220×8/1 = V²

v = $\sqrt{220 \times 8}$

V = 118.6

Answer 2

HEAT = I²RT

I×IRT

SINCE, V = IR

HEAT = IVT

220 = V/R × VT

220 = V²T/R

220×8/1 = V²

v = \sqrt{220 \times 8}

220×8

V = 118.6