Question

220 J of heat is produced each second in a 8 ohm resistor. Find the potential difference across the resistor.​

Answer 1

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HEAT = I²RT

I×IRT

SINCE, V = IR

HEAT = IVT

220 = V/R × VT

220 = V²T/R

220×8/1 = V²

v = $\sqrt{220 \times 8}$

V = 42

Answer 2

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HEAT = I²RT

I×IRT

SINCE, V = IR

HEAT = IVT

220 = V/R × VT

220 = V²T/R

220×8/1 = V²

v = $\sqrt{220 \times 8}$

220×8

V = 42