Question

220. Three unbiased coins are tossed. What is the probability of getting all heads?
Ops: A. O 3/8
B. O 2/9
C. O 1/8
D. O None of the mentioned options​

Answer 1

Answer:

E1={HHH} and, therefore, n(E1)=1. ∴ P (getting all heads) =P(E1)=n(E1)n(S)=18

Answer 2

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =n(E)/n(S)=7/8.

option d is the right answer.