Question

220Volt-100W is written on a bulb .If we connect the bulb with a line of 110V what will be the power?

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Answer 1

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$\sf P = \frac{V {}^{2} }{R} \\ \bf Cross \: multiplying \\ \sf R= \frac{V {}^{2} }{P} \\ \sf R= \frac{220 \times 220}{100} = 484 Ω \\ \sf The \: current \: flow \: in \: circuit, \: i = \frac{110}{484} = 0.2272A \\ \sf \green{The \: voltage \: drop \: across \: the \: bulb \: is \: 110V} \\ \sf The \: power \: consumed \: by \: the \: bulb, \: P_b = \frac{110 \times 110}{484} = 25W \\ \sf P_b = 25W$

Answer 2

★$\underline{\bf{QUESTION :-}}$

220Volt-100W is written on a bulb .If we connect the bulb with a line of 110V what will be the power?

★$\underline{\bf{Answer :-}}$

$\begin{gathered} \sf P = \frac{V {}^{2} }{R} \\ \bf Cross \: multiplying \\ \sf R= \frac{V {}^{2} }{P} \\ \sf R= \frac{220 \times 220}{100} = 484 Ω \\ \sf The \: current \: flow \: in \: circuit, \: i = \frac{110}{484} = 0.2272A \\ \sf \pink{The \: voltage \: drop \: across \: the \: bulb \: is \: 110V} \\ \sf The \: power \: consumed \: by \: the \: bulb, \: P_b = \frac{110 \times 110}{484} = 25W \\ \sf P_b = 25W\end{gathered}$

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