(221x3 + 154x2 + 228x + 41) / (17x + 4)
Answers
Given : (221x3 + 154x2 + 228x + 41) / (17x + 4)
To Find : Quotient and remainder
Solution:
13x² + 6x + 12
17x + 4 _| 221x³ + 154x² + 228x + 41 |_
221x³ + 52x²
___________________
102x² + 228x + 41
102x² + 24x + 41
___________________
204x + 41
204x + 48
___________________
-7
Quotient 13x² + 6x + 12
remainder = - 7
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p(x)=(221x3 + 154x2 + 228x + 41)
g(x)=17x + 4
q(x)=13x^2+6x+12
r(x)=-7