Question

222g of cacl2 is dissolved in 10L of water and its molarity of cl- is 4×10*-n then find value of n

Answer 1

Answer:

Molarity ( M) = # of moles of solute / volume of solution (L)

Volume of Solution = 100 mL or 0.1 L

moles of Ca

C

l

2

= mass of Ca

C

l

2

/ molar mass of Ca

C

l

2

moles of Ca

C

l

2

= 11g / 111 g

m

o

l

−

1

= 0.099 mol

Molarity ( M) = # of moles of solute / volume of solution (L)

Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L