Question

224 ml of triatomic gas weights 1g at 173k and 1atm .The mass of one atom of this gas is

Answer 1

answer..........done

Answer 2

Answer:Then mass of one atom of the gas 21.11 g/mol.

Explanation:

P = 1 atm

T = 173 K

V= 224 mL= 0.224 L

R = 0.0820 atm L/mol K

number of moles (n) = $\frac{\text{given mass}}{\text{molar mass}}=\frac{1 g}{\text{molar mass of the gas}}$

PV=nRT

$1 atm\times 0.224 L=\frac{1 g\times 0.0820 L atm/K mol \times 173 K}{\text{molar mass of the gas}}$

molar mass of gas = 63.33 g/mol

Mass of triatomic gas is 63.33 g/mol

Then mass of one atom of the gas = $\frac{63.33 g/mol}{3}=21.11 g/mol$