22400mL of a volume contain triatomic gas at stp has mass of 48g.The mass of 1 atom of the element is:
a) 2.656×10^-23g
b)3.50×10^-24g
c)6.26×10^-25g
d)1.66×10^-22g
e)2.656×10^-21g.
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Explanation:
molar mass =48g=1 Mole
no of atoms=3×avagadro no
Mass of 3×6.022×10^23 =48g
therefore,Mass of 1 atom= 48/3×6.022×10^23
=2.65×10^-23g.
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