Math, asked by vedhavarsha, 11 months ago

225
C 225
14. The decimal expansion of 0.225 in its rational form is... (J'18)
A 225
15. Every even positive integer can be written in the form of ... (J'18)
A 2p+1(PEZ)
C. 2p -- 1 (
PEZ)
B. 2p EZ)
D. 3p (DEZ)
16. The exponential form of loga Vx'-y is .......(M'19)
A.
WY
B . "-4
17. The last(unit place) digit of 6" in its standard form is .......(M 19)
A. 6
C. 9
18. If log o 2 - 0.3010, then log1932 is ........(I'19)
A.5.3010
B.2.3010 IP C. 1.5050
D. &- a²
-
B.
4
D.
19
1.SOSO
D.0.3010
SETS
.
1.
2.
3.
In venn diagram given below...... (MINIS)
A. AUB -
9, 10
B. AUBE
C. AB -
D. AOB = 0
Set A = {FL, W,0} Which of the following is not a sct builder form for set A (J'15)
A {x:x is a letter from the world FOLLOW
B. {x:x is a letter from the world FLOW)
C. (x:x is a letter from the world WOLF)
D. (x:x is a letter from the world SLOW)
If the union of two sets is one of the set itself, then the relation between
in the two sets is
(J'15)
A One set is a subset of other set C. Equal number of elements of both the sets
B. Disjoint sets
D. Empty sets
Which one of the following is the example of finite set? (M"16)
A. {X/XEN and x = 9
B. Set of rational numbers between 2 and 3.
C. Set of all multiples of even prime numbers.
D. Set of all odd prime numbers.
Number of sub-sets of a set o is... ...(M'16)
A 0
B. 1
C. 3
D. 4
Which one of the following statement is false (J'16)
A. Every set is subset of itself
C. Intersection of two disjoint sets is empty set
B. Empty set is subset of every set D. Cardinal number of an infinite set is zero.
4.
5.
6.​

Answers

Answered by harman28032
1

Answer:

First convert 0.225 into a whole number, so you have to multiply it with 1000. 

Now divide it by the 1000, so 225/1000.

Now simplify that. They are both divisible by 25. 

225/25=9

1000/25=40

Hence, 9/40 is the simplest form. And 9/40=0.225

hope it is helpuful.

please mark in brain list.

Answered by DIVISHASACHDEVA
4

Answer:

hey mate your question is very long and also not understandable......

sorry......

hope you understand...

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