Math, asked by ammukuty1, 1 year ago

22a+15b=5,55a+40b=13 solve using elimination and find a and b

Answers

Answered by Swarup1998
3
➡HERE IS YOUR ANSWER⬇

Given that :

22a + 15b = 5 .....(i)

55a + 40b = 13 .....(ii)

Now, multiplying (i) and (ii) by 55 and 22 respectively, we get :

1210a + 825b = 275

1210a + 880b = 286

On subtraction, we get :

- 55b = - 11

=> b = 1/5

From (i), putting a = 1/5, we get :

22a + 15(1/5) = 5

=> 22a + 3 = 5

=> 22a = 2

=> a = 1/11

Therefore, the required solution is

a = 1/11 and b = 1/5.

⬆HOPE THIS HELPS YOU⬅
Answered by komal248
0
b=1/5 and a= 1/11 answer of this question
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