22a+15b=5,55a+40b=13 solve using elimination and find a and b
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➡HERE IS YOUR ANSWER⬇
Given that :
22a + 15b = 5 .....(i)
55a + 40b = 13 .....(ii)
Now, multiplying (i) and (ii) by 55 and 22 respectively, we get :
1210a + 825b = 275
1210a + 880b = 286
On subtraction, we get :
- 55b = - 11
=> b = 1/5
From (i), putting a = 1/5, we get :
22a + 15(1/5) = 5
=> 22a + 3 = 5
=> 22a = 2
=> a = 1/11
Therefore, the required solution is
a = 1/11 and b = 1/5.
⬆HOPE THIS HELPS YOU⬅
Given that :
22a + 15b = 5 .....(i)
55a + 40b = 13 .....(ii)
Now, multiplying (i) and (ii) by 55 and 22 respectively, we get :
1210a + 825b = 275
1210a + 880b = 286
On subtraction, we get :
- 55b = - 11
=> b = 1/5
From (i), putting a = 1/5, we get :
22a + 15(1/5) = 5
=> 22a + 3 = 5
=> 22a = 2
=> a = 1/11
Therefore, the required solution is
a = 1/11 and b = 1/5.
⬆HOPE THIS HELPS YOU⬅
Answered by
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b=1/5 and a= 1/11 answer of this question
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