Question

22g chunk of dry ice is placed in a empty 600ml tightly closed vesselat 25 °c what would be the final pressure inside the vessel if all co2 gas is evaporated
20.4 atm
19.4 atm
3.71atm
21.4 atm ​

Answer 1

w = 22g dry CO2 which will evaporate to develop P

m = 44

V = 0.6 litre

P = ?

T = 298 K

PV = wmRT

P×0.6=2044×0.0821×298

Pressure inside bottle = P + atm. pressure

w = 22g dry CO2 which will evaporate to develop P

m = 44

V = 0.75 litre

P = ?

T = 298 K

PV = wmRT

P×0.6=2044×0.0821×298

⇒ P = 8.334 atm

Pressure inside bottle = P + atm. pressure

⇒ 8.334 + 1 = 9.334 atm

Answer 2

Answer:

The final pressure inside the vessel, if all CO₂ gas is evaporated is 21.4 atm.

Explanation:

Given,

The weight of dry ice (CO₂) is w = 22g.

The volume of vessel is (V) = 600 ml = 0.6 L

The temperature at which the vessel is (T) = 25°C = 25 + 273 = 298 K.

Gram molecular weight (M) = 44g.

To find,

The final pressure inside the vessel, if all the CO₂ gas is evaporated (P).

Calculation,

Dry ice is a solid form of carbon dioxide (CO₂).

Let the pressure inside due to CO₂ be 'p'.

Now from the ideal gas equation:

pV = nRT

pV = (w/M) × RT

p(0.6) = (22/44)(0.0821 × 298)

p = 20.4 atm

Now, the total pressure inside the vessel, if all CO₂ gas is evaporated, is:

P = p + atmospheric pressure.

P = 2.4 + 1

P = 21.4 atm.

Therefore, the final pressure inside the vessel, if all CO₂ gas is evaporated is 21.4 atm.

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