Question

22g of water at 30C is mixed with an equal amount of water at 60C. Then find the resultant temperature of the mixture ​

Answer 1

Answer:

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Answer 2

Given:

22g of water at 30°C is mixed with an equal amount of water at 60°C.

To find:

Resultant temperature of mixture ?

Calculation:

This is a question from CALORIMETRY , Let the final temperature of the mixture be $\theta$.

According to PRINCIPLE OF CALORIMETRY,

$\therefore \: m_{1} \times c \times \Delta \theta_{1} =m_{2} \times c \times \Delta \theta_{2}$

$\implies \: 22 \times \Delta \theta_{1} =60 \times \Delta \theta_{2}$

$\implies \: 22 \times ( \theta - 30)=22 \times(60 - \theta)$

$\implies \: \theta - 30 = 60 - \theta$

$\implies \: 2 \theta = 90$

$\implies \: \theta = {45}^{ \circ}$

So, temperature of mixture is 45°.