Math, asked by janakdatta16, 9 months ago

22question
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Answers

Answered by shivika35
0

Answer:

(19/3)x^2 - (5/3)x - 56/3

Answered by sntarakeshwari
1

Answer:

Answer:-9x^{2}+7x-56

Step-by-step explanation:

Sum of 7x^{2}-4x+6 and -x/3+13

7x^{2}-4x+6+13-x/3

7x^{2}-4x-x/3+19

7x^{2}12x-x/3+19

7x^{2}-13x/3+19

21x^{2}-13x+57----------equation 1

Sum of 13x^{2}-5x+1/3 and 1/3x^{2}-x

13x^{2}-5x+1/3 + 1/3x^{2}-x

13x^{2}+1/3x^{2}-5x-x+1/3

29x^{2}+x^{2}/3-6x+1/3

30x^{2}/3-6x+1/3

10x^{2}-6x+1/3

30x^{2}-6x+1--------------equation 2

According to the question we have to subtract equation 1 from equation 2

30x^{2}-6x+1-(21x^{2}-13x+57)

30x^{2}-21x^{2}+13x-6x+1-57

Answer:-9x^{2}+7x-56

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