22x-18y =57 and 12x+18x =27 than x+y=?
Answers
Answer:
Given,
12x+17y=48×12
17x+12y=68×17
144x+204y=576
289x+204y=1156
−145x=−580
x=4
substitute x value in the 1st equation
12×4+17y=48
48+17y=48
17y=0
then
x-y=4-0=4
Step-by-step explanation:
22x - 18y = 57
22x = 57 + 18y
x = (57 + 18y)/22 --------- (1)
12x + 18x = 27
30x = 27
x = 27/30
x = 9/10
Substitute value of x in (1)
9/10 = (57 + 18y)/22
9/5 = (57 + 18y)/11
9(11)/5 = 57 + 18y
99/5 = 57 + 18y
99/5 - 57 = 18y
(99 - 285)/5 = 18y
-186/5 = 18y
-186/(5*18) = y
-10.33/5 = y
-2.07 = y
Now,
→ x + y = 9/10 + (-2.07)
→ x + y = 0.9 - 2.07
→ x + y = -1.17
Hence, the value of x + y is -1.17.
If Question is: 22x-18y =57 and 12x+18y =27 than x+y=?
Solution: 22x - 18y = 57
22x = 57 + 18y
x = (57 + 18y)/22 --------- (1)
12x + 18y = 27
3(4x + 6y) = 3(9)
4x + 6y = 9
2[(57 + 18y)/11] + 6y = 9
2[(57 + 18y + 66y)/11] = 9
2(57 + 84y) = 99
114 + 168y = 99
168y = -15
y = -15/168 or -0.09
Substitute value of y in (1)
x = [(57 + 18*(-15/168))/22]
x = [(57 + 3(-15/28))/22]
x = (1596 - 45)/616
x = 1551/616
x = 2.52
→ x + y = 2.52 - 0.09 = 2.43