Question

2³^0+2²^9+2²^8/2³¹+2³^0-2²^9 = 7/10 prove that ​

Answer 1

How (2³⁰ +2²⁹ +2²⁸)/(2³¹ + 2³⁰ -2²⁷)=7/10? “

So to prove,

(2³⁰ +2²⁹ +2²⁸)/(2³¹ + 2³⁰ -2²⁹) = 7/10

1. Consider LHS.
2. Take 2²⁸ common in numerator and 2²⁹ in denominator.
3. Use Law of Exponents for these common terms (a^m /a^n =a^(m-n) and a^(-p) = 1/(a^p) ).
4. Simplify the remaining terms in bracket so formed.
5. Reduce further to get 7/10
6. LHS=RHS is achieved.
7. Hence proved.