Question

23 (1)
1 + sin A
V1-sin A
= tan A + sec A​

Answer 1

$\sqrt{ \frac{1 + sina}{1 - sina} } \\ \\ = \sqrt{ \frac{1 + sina}{1 - sina} \times \frac{1 + sina}{1 + sina} } \\ \\ = \sqrt{ \frac{( {1 + sina})^{2} }{ {cos}^{2} a} } \\ \\ = \frac{1 + sina}{cosa} \\ \\ = seca + tana$