Question

23 A and B have some money with them. A said to B, 'if you give me 100, my money
will become 75% of the money left with you'. "B said to A" instead if you give me
100, your money will become 40% of my money. How much money did A and B
have originally?​

Answer 1

Step-by-step explanation:

A and B have some money with them, A said to B, ' if you give me Rs.100, my money will become 75%=0.75 of the money left with you. 'B said to A, 'instead if you give me Rs100, your money will become 40%=0.40 of my money.'

As per 1st condition:(A+100)=0.75(B−100)

This gives us the value of A=0.75B−175 -------------- (i)

As per the 2nd condition: (A−100)=0.40(B+100)

This gives us the value of A=0.40B+140 -------------- (ii)

Equating (i) and (ii), we get B=900

Inputting this value in (i), we get the value of A=500

So originally, A had Rs.500 and B had Rs.900

Answer 2

Answer:

A = 500 , B = 900

Step-by-step explanation:

Let’s assume A has money = x

And B has money = y

Then according to the given conditions, we have

x – 100 = (y – 100) x (75/100)

x – 100 = (y – 100) x (3/4)

4x – 400 = 3y – 300

4x – 3y = 400 – 300

4x – 3y = 100 … (i)

Also,

x – 100 = (y + 100) (40/100)

x – 100 = (y + 100) (2/5)

5x – 500 = 2y + 200

5x – 2y = 200 + 500

5x – 2y = 700 … (ii)

Now, multiplying (i) by 2 and (ii) by 3, we have

8x – 6y = -1400

15x – 6y = 2100

(-)—(+)—(-)—-

-7x = -3500

x = -3500/ -7

x = 500

On substituting the value of x in (i), we get

4(500) – 3y = -700

2000 – 3y = -700

3y = 2000 + 700

y = 2700/3

y = 900

Therefore, A has money Rs 500 and B has money Rs 900.