Question

23. A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the
bag is twice that of a red ball, find the number of blue balls in the bag.
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Answer 1

Answer:

STEP BY STEP EXPLAIN ATION

Number of Red balls =n(R)=6

Let, no. of blue balls be x, n(B)=x

Total no. of balls in bag=n(T)=6+x

We know that, Probability P(Event) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

Probability of drawing a red ball, P(R)=

6+x

n(R)

Probability of drawing a blue ball, P(B)=

6+x

n(B)

Given,

Probability of drawing a blue ball from the bag is twice that of a red ball

I.e., P(B)=2×P(R)

6+x

n(B)

=2×

6+x

n(R)

x=2×6

n(B)=x=12

Total no. of balls in bag=n(T)=6+x=6+12=18 balls