.23. A bead starts sliding from a point P on a frictionless wire with initial velocity of 5 ms−1. Find the velocity of bead at point R (take g = 10 ms−2)
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The value of velocity should be around 7.939 m/s
(Exp:
At state A:
Kinetic Energy =1/2m(4)^2.
Potential Energy=mg(5).
At state B:
Kinetic Energy =1/2m(V)^2.
Potential Energy=mg(2.6).
:- so the law of conservation of energy
(Exp:
At state A:
Kinetic Energy =1/2m(4)^2.
Potential Energy=mg(5).
At state B:
Kinetic Energy =1/2m(V)^2.
Potential Energy=mg(2.6).
:- so the law of conservation of energy
ashwinisangeetp9hug7:
formula likhe samjha dijie pls
it is clearly understandable
see the question and see the answer
you are going to get
velocity 5ms h
tumne galat solve kiya h
sry sahi h
ab dekho
got it
formula bta do ek baar
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