Question

23. A box contains 90 discs which are numbered
from 1 to 90. If one disc is drawn at random from the
box, find the probability that it bears (i) a two - digit
number, (ii) a perfect square number, (iii) a number
divisible by 5, (iv) a prime number less than 30.​

Answer 1

Answer:

hope it helps you mate.

Step-by-step explanation:

1. p(E) = 89/90
2. perfect square number between 1 to 90 are ( 1, 4,9,16,25,36,49,64,81) therefore p(E) = 9/90 = 1/10
3. number divisible by 5 are (5, 10, 15, 20,25,30,35,40,45,50,55,60,65,70,75,80,85,90) then p(E) = 18/90 = 1/5
4. prime number less than 30 are ( 2, 3, 5, 7, 11, 13, 17, 19, 23, 29) then p(E) = 10/90 = 1/9