23.) A burner raises the temperature
of 500g of water from 10°C to 100°C
in 5 mins. The power of the burner is
calculated to be -
*
Answers
Answer:
m = mass of water = 500g, θ1 = Initial temperature = 100C
c = Specific heat capacity of water = 4.2 J/g0C, θ2 = Final temperature = 1000C
Let Q be heat supplied by Bunsen burner = Q
Heat lost by Bunsen burner = Heat gained by water (Law of calorimetry)
Q = mc (θ2 – θ1)
Q = 500 x 4.2 x (100 -10)
Q = 500 x 4.2 x 90
Q = 189000 J
Heat supplied by burner per second Q = Total Heat/time = 189000/300s J
Heat supplied per second is 630 J/s.
Explanation:
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Answer:
m = mass of water = 500g, θ1 = Initial temperature = 100C
c = Specific heat capacity of water = 4.2 J/g0C, θ2 = Final temperature = 1000C
Let Q be heat supplied by Bunsen burner = Q
Heat lost by Bunsen burner = Heat gained by water (Law of calorimetry)
Q = mc (θ2 – θ1)
Q = 500 x 4.2 x (100 -10)
Q = 500 x 4.2 x 90
Q = 189000 J
Heat supplied by burner per second Q = Total Heat/time = 189000/300s J
Heat supplied per second is 630 J/s.
Explanation:
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