23. A charge of 240 C is transferred in 2 minutes. The current
flowing is
(A) 480A
(B) 120A
(C) 2A
(D) 8A
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2
Answer:
the answer is (C) 2A...
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- charge (coulomb, C)= 240C.
- Time = 2min. = 2×60 = 120 sec.
charge (coulomb, C) = current (ampere, A) × time (second, s).
Putting value in formula we get,
240 = I × 120
I = 240/120
I = 2A
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